The Math Forum

For anyone with a love of math
 
HomeHome  ­CalendarCalendar  ­GalleryGallery  ­FAQFAQ  ­SearchSearch  ­MemberlistMemberlist  ­UsergroupsUsergroups  ­RegisterRegister  ­Log inLog in  
Post new topic   Reply to topicShare | 
 

 Lesson 1, Problem 2

View previous topic View next topic Go down 
AuthorMessage
Dojo
Admin
Admin


Number of posts: 154
Location: Probably somewhere near a computer
Registration date: 2008-08-13

PostSubject: Lesson 1, Problem 2   Fri Aug 15, 2008 5:38 pm

2) How many numbers are in the set:
3,6,9,12...42?

_________________
~Dojo
Back to top Go down
View user profile http://themathforum.forumotion.com
herefishyfishy1
Developer
Developer


Number of posts: 36
Age: 14
Location: An insignificant little blue-green planet 93 million miles from the sun Sol.
Registration date: 2008-08-16

PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 6:59 am

42-3=39.
39/3=13
13+1=14.

14 is the answer.
Back to top Go down
View user profile
Dojo
Admin
Admin


Number of posts: 154
Location: Probably somewhere near a computer
Registration date: 2008-08-13

PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 11:58 am

Thats one way, but is there a slicker way?
See lesson 1 and the answer key.

_________________
~Dojo
Back to top Go down
View user profile http://themathforum.forumotion.com
AIME15
Hardcore TMF user
Hardcore TMF user


Number of posts: 163
Age: 13
Location: Pleasanton, CA
Registration date: 2008-08-13

PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 12:38 pm

Divide the whole thing by 3, to get 1-14. So there's 14 numbers.
Back to top Go down
View user profile
 

Lesson 1, Problem 2

View previous topic View next topic Back to top 
Page 1 of 1

Permissions of this forum:You cannot reply to topics in this forum
The Math Forum :: Dojo's Math Encyclopedia (Unfortunately sadly small) :: Counting & Probablilty-
Post new topic   Reply to topic