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 Lesson 1, Problem 2

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Dojo
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PostSubject: Lesson 1, Problem 2   Fri Aug 15, 2008 6:38 pm

2) How many numbers are in the set:
3,6,9,12...42?

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herefishyfishy1
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PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 7:59 am

42-3=39.
39/3=13
13+1=14.

14 is the answer.
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PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 12:58 pm

Thats one way, but is there a slicker way?
See lesson 1 and the answer key.

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AIME15
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PostSubject: Re: Lesson 1, Problem 2   Sat Aug 16, 2008 1:38 pm

Divide the whole thing by 3, to get 1-14. So there's 14 numbers.
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